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Help me to analyze the H NMR spectrum of 2chloro 2methylbutane?
Sample H NMR spectrum taken of student products industry of 2-chloro-2-methylbutane C5H11Cl http://img33.imageshack.us/i/74163576.jpg/ particular alert arising from the expected product. Explain the division of each set of peaks, their locations on the radio spectrum (protons are protected or deshielded) and their relative integral values. How can To find out if they are dirty? If you find data to identify the substance mixture of peaks and their use the integrated value of these peaks to calculate the molar ratios of product and contaminants. I was able indicate some of the peaks in this http://img35.imageshack.us/i/10360847.jpg/ but the rest of the matter is so hard!
Okay so, the easiest to see the 4-plet of 1.78, which can only be CH2 than expected your product (such as your DB Keyword confirmed). Split of CH3, so it becomes in the Quartet will now expect to see additional high shirt 1.5 (the other two CH3s, which not divided into anything) at 1,0 and three of the last CH3 dividing to CH2, it is a pure compound What you see are two trios around 1,0, another high of 1,2 t-shirt and something that could Four to be in 1.4. So there are four impurity 1,4, high singlet 1,2 and 1.0 for a triple that looks almost exactly like his compound but shifted to the right. I guess that of the corresponding alcohol, no oxygen is so strong in deshielding as chlorine, and this will make chemical sense to have as an impurity. Now let's look at the DB for 2-methyl-2-butanol A 1.52 B 1.49 C 1.197 D 0.924 where A is-OH, B is-CH2-, C is two CH3s, which have high singlet and development is one forming a triple-CH3. So here it is, I think that your case is too-OH 1,49, overlapping is a component of four of CH2, but I do not charge by measuring the heights integral for you:)